Raonic survives four-hour marathon against Wawrinka
Sacha Pisani
January 17, 2019 06:51 MYT
January 17, 2019 06:51 MYT
Milos Raonic outlasted Stan Wawrinka in a gruelling four-set shoot-out to book his spot in the third round of the Australian Open.
Raonic survived 6-7 (4-7) 7-6 (8-6) 7-6 (13-11) 7-6 (7-5) against 2014 champion Wawrinka after more than four hours in Melbourne on Thursday, marking the longest match the Canadian star has won in his career.
Four tie-breaks were needed as 16th seed Raonic - a quarter-finalist or better in three of the past four years at Melbourne Park - prevailed in humid conditions on Rod Laver Arena.
Raonic fired down 39 aces compared to Swiss Wawrinka's 28, while he topped the winners column 84-66 en route to the next round.
MIGHTY MILOS!@milosraonic gets past a resurgent Wawrinka, 6-7(4) 7-6(6) 7-6(11) 7-6(5).#AusOpen #GameSetMatch pic.twitter.com/ybUvMh9GKR — #AusOpen (@AustralianOpen) January 17, 2019
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Next up for Raonic is Frenchman Pierre-Hugues Herbert.